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what is the solution set x^2+5x-6=0
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un-foil it what multiplys to get -6 and also adds to 5
at this point if you can't find the numbers then use the quadratic equation. \[ax^2 +bx+c\] plug the variables a, b and c into the equation. \[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
what are 2 numbers that, when multiplied equal to -6, but when added equal to +5? those 2 numbers are 5 and -1. so (x-1)(x+5)=0 now we have 2 solutions. x-1=0 x=1 and x+5=0 x=-5.
not 5 and -1. Its 6 and -1.
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