The force acting between two charged particles A and B is 5.2 × 10-5 newtons. Charges A and B are 2.4 × 10-2 meters apart. If the charge on particle A is
7.2 × 10-8 coulombs, what is the charge of particle B?
(k = 9.0 × 109 newton·meters2/coulomb2)

Question

The force acting between two charged particles A and B is 5.2 × 10-5 newtons. Charges A and B are 2.4 × 10-2 meters apart. If the charge on particle A is
7.2 × 10-8 coulombs, what is the charge of particle B?
(k = 9.0 × 109 newton·meters2/coulomb2)

anonymous · Answer

$$F=\frac{k*Q_A*Q_B}{d^2}$$
$$5.2*10^{-5}=\frac{9*10^9*7.2*10^{-8}*Q_B}{(2.4*10^{-2})^2}$$
$$\boxed{\boxed{Q_B=4.62*10^{-11}~C}}$$

sammixboo · Answer

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anonymous · Answer

thanks :3 for helping D3xt3R ^.^)... and thanks sammixboo  :)

sammixboo · Answer

no problem @galaxy_00