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Mathematics 15 Online
OpenStudy (camerondoherty):

http://prntscr.com/3yt2qu

OpenStudy (anonymous):

i believe it is the 1st one because 2nd and 4th choices are just small rugs for the dyeing process and mediums for the knotting... and for the 3rd one 4S=4*12=48 which is already larger than the 40 hour max... so i say the 1st one is your answer

OpenStudy (aum):

To make 'S' small size rugs per week would require 2S hours of dyeing and 4S hours of knotting per week. To make 'M' medium size rugs per week would require 3M hours of dyeing and 6M hours of knotting per week. Total dyeing time per week = 2S + 3M Total knotting time per week = 4S + 6M Total dyeing time per week <= 40. Therefore, 2S + 3M <= 40 Total knotting time per week <= 50. Therefore, 4S + 6M <= 50 Put S = 12 and M = 5 and you will notice the second constraint won't hold and therefore 12 small rigs and 5 medium rugs cannot be made per week because of one of the restrictions: 2S + 3M <= 40 and 4S + 6M <= 50

OpenStudy (anonymous):

so yes it is the 1st option

OpenStudy (camerondoherty):

lol Thanks you two!

OpenStudy (anonymous):

anything for you cam ;)

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