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Trigonometry Help (only 4 left!) Prove the Identity: sec^2 x= (4sin^2 x)/(sin^2 x)
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are you sure the question is complete and correct
|dw:1404370996175:dw| is what the problem looks like
now the question is different from what you posted
yeah a tiny bit, go by the picture, the picture is correct. that was an accident
do u know sin2x = 2sinx cosx
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sin 2x or sin^2 x?
nvm sin 2x
so sec^2 x = 1/cos^2 x = (1/cos^2 x) * (sin^2 x/sin^2 x )
(sin^2 x/( cos^2 x *sin^2 x )) =(4*sin^2 x/(4* cos^2 x *sin^2 x )) = 4*sin^2 x /(2sinx cosx)^2 = 4*sin^2 x /(sin2x)^2
hope it is clear to you
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