Question

y = sqrt(x+sqrt(x))

Answer 1

\[y=\sqrt{x+\sqrt{x}}\]
\[y ^{2}=x+\sqrt{x} => \sqrt{x}=y^{2}-x\]
squaring again..
\[x=(y ^{2}-x)^2\]
\[x=y^4+x^2-2xy^2\]
\[y^4+2xy^2-x-x^2=y^4+x(2y^2-1)-x^2\]