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OpenStudy (yanasidlinskiy):
\(\Huge\bf \color{yellow}{Welcome~to~OpenStudy!!}\hspace{-310pt}\color{cyan}{Welcome~to~OpenStudy!!}\hspace{-307.1pt}\color{midnightblue}{Welcome~to~\color{purple}{Open}}\color{blue}{Study!!}\)
Hello, Jianne.
Do you mean like:
mean,median mode range?
OpenStudy (anonymous):
no .are u 4th year?
OpenStudy (anonymous):
im not sure which range...
OpenStudy (yanasidlinskiy):
Can you clear up your question a little? I don't understand..
OpenStudy (anonymous):
i mean that if your a 4th a 4th year high school because my question is for 4th year
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OpenStudy (yanasidlinskiy):
Well, I'm finishing up 12th grade!:D
OpenStudy (anonymous):
wait yes there is seniors crap
OpenStudy (anonymous):
oh. so you already know how to get the different of of square
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so can you teach me
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OpenStudy (anonymous):
sure
OpenStudy (anonymous):
so lets get started
OpenStudy (anonymous):
ok... bring it on!!!
OpenStudy (anonymous):
3x^2-3x-36
OpenStudy (yanasidlinskiy):
It would equal 0. Right?
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OpenStudy (anonymous):
well this is a trinomial there will be 2 solutions.
so 3x^2 - 3x - 36 right so... this is my way of figuring it out.
First FOR 3 = 3 * 1 and for 36 you can use -36 = -4 * 9.
Then you can see if they add up to -3
3 *- 4 = - 12 and 1 * 9 = 9
-12+9 = -3
then you put it together
(3x + 9)(x -4)
so x = -3 or 4