Question

solve the quadratic equation:
2x^2-7x+1=0

Answer 1

and show work

Answer 2

Help please

Answer 3

According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :

- B ± √ B2-4AC
x = ————————
2A

In our case, A = 2
B = -7
C = 1

Accordingly, B2 - 4AC =
49 - 8 =
41

Applying the quadratic formula :

7 ± √ 41
x = —————
4

√ 41 , rounded to 4 decimal digits, is 6.4031
So now we are looking at:
x = ( 7 ± 6.403 ) / 4

Two real solutions:

x =(7+√41)/4= 3.351

or:

x =(7-√41)/4= 0.149

Answer 4

thank you so so much!

Answer 5

welcome