Question

Help on 2 precalc problems please

Answer 1

http://prntscr.com/3z2kgw

Answer 2

http://prntscr.com/3z2pyc

Answer 3

for the first one i picked all real numbers except -4 and 6 and it was wrong for the second one i picked all real numbers and it was wrong

Answer 4

The numerator has a square root. Square root is not defined for negative numbers (at least not for real values) and so x + 1 has to be greater than or equal to 0. Additionally, x cannot be -4 or 6. Combine all the conditions.

Answer 5

so the first question would be A?

Answer 6

x + 1 >= 0 or x >= -1
x cannot be -4. If the above condition is satisfied x will not be -4 and so this condition is already part of the previous condition and therefore can be ignored.
x cannot be 6.

So x x >= -1 and x cannot be 6.

Answer 7

Yes, A.

Answer 8

Ok, I dont need help on the second one anymore but could you help me on a different one?

Answer 9

Sure.

Answer 10

Do you want me to open a new question or is here fine?

Answer 11

If it is just one more it is fine to do it here.

Answer 12

I think this one is B
http://prntscr.com/3z315w

Answer 13

Yes.

Answer 14

Thank you!

Answer 15

You are welcome.