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Mathematics 14 Online
OpenStudy (anonymous):

2^x=4^x+1

OpenStudy (campbell_st):

well use some index laws to write both terms in the same base \[2^x = (2^2)^{x + 1} ... or..... 2^x = 2^{2x + 2}\] now you can equate the powers and solve for x

OpenStudy (anonymous):

Thanks so much! :D

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