Given: Triangle HJF ANGLE F CONG, ANGLE J HF=X+6 HJ=3X-2 FJ=3X BY SOLVING FOR X, FINF THE PERIMETER OF TRIANGLE HJF
ANGLE F CONG, ANGLE J so HF = HJ (sides opposite to equal angles are equal) so we can write x+6 =3x-2
i hope you can do further
i got x=4 and then I substitute, but my answer were not one of the choices. the choices are: 8 , 14, 24, 54
perimeter of the triangle is given by the sum of the sides x=4 is correct now try to find the length of each side
HF= 10 HJ=10 FJ=12 is this correct?
yup
but, when i added them up , it was not one of the choices
hmmm but what you have done so far is always correct
the choices are: A. 8 B. 14 C. 24 D. 54
for the question you posted you have claculated the correct answer.. can you recheck your question...
its written correctly, I think theres a mistake in the question. Thank you for your help. Im going to close the question.
yw either one of them is incorrect
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