Question

y = x2 + 4x - 12

Answer 1

find the x- intercepts

Answer 2

@matricked

Answer 3

for findind x-intercepts put y =0

Answer 4

y = x2 + 4x - 12
so
0=x2 + 4x - 12
and then factorise...

Answer 5

oh

Answer 6

x^2+6x-2x-12

Answer 7

then (x^2+6x) (-2x-12)?

Answer 8

x2 + 4x - 12 =0
so
x2 + 4x - 12 =0
x2 +(6-2)x -12 =0 [4 = 6-2]

Answer 9

yup proceed you r in correct direction...

Answer 10

(x+6) (x-2)?

Answer 11

x2 +(6-2)x -12 =0
x2 +6x-2x -12
x(x+6) -2(x+6) = 0
(x+6)(x-2) =0

Answer 12

yay!

Answer 13

x=-6 and x=2 right?

Answer 14

yup

Answer 15

thx you :3

Answer 16

yw

Answer 17

can you help with 1 more?