You are making poster board boundary markers in the shape of square pyramids for a relay race. If you are including a ten -inch square as the bottom and you want the slant height to be twelve inches, how much poster board do you need?
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OpenStudy (anonymous):
a.340
b.360
c.384
d.400
plzzz help...
OpenStudy (anonymous):
@dan815
OpenStudy (anonymous):
@Hero
OpenStudy (anonymous):
someboody pleaze help
OpenStudy (anonymous):
@ganeshie8
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OpenStudy (anonymous):
@Hero
hero (hero):
Do you know the formula for square pyramid?
OpenStudy (anonymous):
V=a2h
3
OpenStudy (anonymous):
V = a^2 h/3
OpenStudy (anonymous):
is that it
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This is not a volume problem but a surface area problem.
Find the area of 1 triangle that forms the side of the pyramid. Multiply it by 4.
Add the area of the square base.
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
what would the answer be
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OpenStudy (aum):
Area of triangle = 1/2 * base * height = 1/2 * 10 * 12. Multiply by 4.
Area of base = 10 * 10
Add them up.
OpenStudy (anonymous):
oooh now i understand :)
OpenStudy (anonymous):
i got 340
OpenStudy (anonymous):
is that correct??
OpenStudy (aum):
I believe so.
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OpenStudy (anonymous):
:) thanks
OpenStudy (aum):
yw.
OpenStudy (anonymous):
yaaaaaas
OpenStudy (anonymous):
i love you tanks
OpenStudy (yanasidlinskiy):
By the way, @Mr_Meagee
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