Question

There are 6 dogs and 5 cats. In how many different orders can these animals be placed in line under the following conditions?

i) Any animal can be next to any other animal.
ii) The dogs and cats are lined up alternately.
iii) The first and last animal in line must be a cat.

Answer 1

_ _ _ _ _ _ _ _ _ _ _

Answer 2

11 slots

Answer 3

multiply

Answer 4

lets assume each dog is different and each cat is different

Answer 5

you can choose either a cat or dog in the first slot : 11 ways

Answer 6

from the remaining 10 catdogs, you can choose either a cat or dog in the second slot : 10 ways

Answer 7

...

Answer 8

I thought only a cat?

Answer 9

10.9.8.7.6.5.4.3.2.1

Answer 10

total number of ways of arranging these = 11*10*... 2*1 = 11!

Answer 11

is this right?

Answer 12

please ganeshie8?

Answer 13

Well ganeshie gave you the answer for the first one, it's 11!

Answer 14

nope

Answer 15

2. The row has two options, so 2*6!*5!

Answer 16

not according to my choices

Answer 17

i) 39,916,800, ii) 86,400, iii) 7,257,600

i) 42,068,100, ii) 88,700, iii) 7,406,800

i) 37,289,400, ii) 90,200, iii) 7127,400

i) 40,157,600, ii) 83,400, iii) 7,348,500

Answer 18

Do you know what a factorial is?

Answer 19

non-negative integer

Answer 20

11! = 11*10*9*8*7...up to 1.

Answer 21

36,288,000

Answer 22

?

Answer 23

How did you get that?

Answer 24

multiply

Answer 25

Check again

Answer 26

all those numbers

Answer 27

On your calculator you should have a prb or probability button, and if you click that you will be able to find a exclamation mark "!" if you use that, it will save you time.

Answer 28

http://www.wolframalpha.com/input/?i=11%21

Answer 29

ok 39,916,800?

Answer 30

so therefore answer has to be A

Answer 31

yes

Answer 32

cool :) thanks

Answer 33

Np :P