Question

Relative minimum
f(theta)=square root 3 times theta - 2 sin(theta)

Answer 1

\[f (\theta)=\sqrt{3} \theta-2\sin \theta\]

Answer 2

take derivative wrt to theta

Answer 3

I found the derivative and set it to zero
\[f ' (\theta)=\sqrt{3}-2\cos(\theta)\]

Answer 4

I thought the answer was pi/6