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Question

anonymous · Answer

Hi welcome to OPenstudy!!
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use your trig ratios, soh cah toa
In this case you should use $\LARGE sin \theta=\frac{opposite}{hypotenuse}$

anonymous · Answer

What do I plug in for the opposite?

anonymous · Answer

you have to arrange it to find the OPPOSITE.

so it will be $\LARGE Opposite=hypotenuse \times sin \theta$

anonymous · Answer

Opposite=x