Question

evaluate. 2 integrals

Answer 1

did you try
\( u= \sqrt y \)

Answer 2

the u sub method

Answer 3

for 1st one, try
\(u =\sqrt y \)

and for 2nd one, try
\(u =\sqrt x \)

Answer 4

for the first one, my du is 1/2 y ^-1/2 dy. and for the 2nd, du = 1/2 x ^-1/2

Answer 5

so
2du = dy/ sqrt y
right ?