2 towns A, B are connected by a regular bus service with a bus leaving in either direction every T min. A man cycling with speed of 20km/hr in the direction A to B notices that the bus goes past him every 18 min in the direction of his motion, and every 6 min in the opposite direction. what is the period T and with what speed (assumed constant) do buses ply on the road?
the 2 equations formed in the answer are:
(v-20)18/60 = v*T ........(1)
(v+20)6/60 =v*T ..........(2)
[where v= velocity of each bus]
how to deduce the 2 equations?

Question

2 towns A, B are connected by a regular bus service with a bus leaving in either direction every T min. A man cycling with speed of 20km/hr in the direction A to B notices that the bus goes past him every 18 min in the direction of his motion, and every 6 min in the opposite direction. what is the period T and with what speed (assumed constant) do buses ply on the road?
the 2 equations formed in the answer are: 
(v-20)18/60 = v*T ........(1)
(v+20)6/60 =v*T ..........(2)
[where v= velocity of each bus]
how to deduce the 2 equations?

anonymous · Answer

Make them equal each other and solve for v as it has the same distance

anonymous · Answer

What do you mean ??

abhisar · Answer

@lall do u know relative velocity ?