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The length of the hypotenuse of an isosceles right triangle is sqrt6 inches. How long, in inches, are the legs of the triangle?
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use this sin90=perp/hypt =>perp=hypt*sin90 =>perp=sqrt6 *1=sqrt6 inches
\[\sqrt{x ^{2}+x ^{2}}=\sqrt{2x ^{2}}=\sqrt{6}\] and solve for x (x is the side length
|dw:1404673950923:dw| let x is the length of legs of the triangle. x sqrt(2) = sqrt(6) solve for x
@Catch.me could u help me with one more?
ok
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