A car starts from xi = 12m at ti = 0 and moves with the velocity graph shown in figure below. What is the objects position and t=3s and t=4s? Picture in comments below
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OpenStudy (anonymous):
OpenStudy (anonymous):
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For t = 3s, find the area of triangle AOB.
OpenStudy (anonymous):
Add this value to initial position 12 m to get the position at t = 3s
OpenStudy (anonymous):
so at t=3s it is 30..
OpenStudy (anonymous):
Correct! Now go for t = 4s..
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OpenStudy (anonymous):
how the are is 30!! it is 3x12x0.5=18 m at 3sec
OpenStudy (anonymous):
and then t=4 is 28 :)
OpenStudy (anonymous):
hey man get area!! at 4 sec
you will minus the 2 triangles 18-2= 16 m
OpenStudy (anonymous):
I got the right answers according to Mastering Physics.. Thank you ShailKumar for telling me how to do this :)
OpenStudy (anonymous):
how did u get 30 for 3sec ??
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OpenStudy (anonymous):
Catch me it is area plus the initial position of 12m
OpenStudy (anonymous):
OK thanks i didn't read your initial question carefully :D
OpenStudy (anonymous):
Happy learning ! :) @zydic and @Catch.me
OpenStudy (anonymous):
@ShailKumar :D , but i do know that concept just didn't read the question carefully :P