Question

Find three consecutive even numbers so that the sum of the first and third numbers is 22 less than three times the second number.

Answer 1

let the smallest number be n. Then the three numbers are n, n+1, and n+2.

n + (n+2) = 3(n+1) - 22

One equation in one unknown. Solve.

Answer 2

Whoops EVEN numbers

So make them n, n+2, n+4

n + (n+4) = 3(n+2) - 22

Answer 3

thank you :)