How could you differentiate a bubble from true specimen?
Need more info.
\(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\Huge\color{pink}{W}\)\(\Huge\color{violet}{e}\)\(\Huge\color{pink}{l}\)\(\Huge\color{violet}{c}\)\(\Huge\color{pink}{o}\)\(\Huge\color{violet}{m}\)\(\Huge\color{pink}{e}\) \(\Huge\color{violet}{t}\)\(\Huge\color{pink}{o}\) \(\Huge\color{violet}{O}\)\(\Huge\color{pink}{p}\)\(\Huge\color{violet}{e}\)\(\Huge\color{pink}{n}\)\(\Huge\color{violet}{S}\)\(\Huge\color{pink}{t}\)\(\Huge\color{violet}{u}\)\(\Huge\color{pink}{d}\)\(\Huge\color{violet}{y}\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\) \(\small\color{magenta}\bigstar\) \(\small\color{lightblue}\bigstar\)
by vision
I think they are meaning when using a light microscope, but I am not sure. If that is the case, by vision will not always work.
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