Question

given f(x)=1/x+3. Find the domain and range

Answer 1

\[f(x)= \frac{ 1 }{ x+3 }\]

Answer 2

Domain:
find where the function in undefined .... set denominator equal to 0
x+3 = 0
x = -3
so domain is all real numbers except -3

Range:
the denominator has higher degree so the horizontal asymptote is y=0
Range is all real numbers except 0

Answer 3

thank you and do you think you could me with another ? i already have the domain i just need the range?

Answer 4

ok

Answer 5

\[\sqrt{x+6}\]

Answer 6

the sqrt of a number is always positive

Range is y>= 0

Answer 7

so how do you write it?

Answer 8

lol
y>= 0

or in interval form ..... [0, infinity)

Answer 9

lol yeah i forgot what it was called but thanks XD

Answer 10

yw