Question

The level of beer in a 11 foot cylindrical key is decreasing at a constant rate of 0.25 feet per minute. If the radius of the keg is 4 feet, at what rate is the beer draining out?

Answer 1

This is a related rates problem

Answer 2

here
V= 16(pi)*h [as r=4]
differentiating wrt t we have
dV/dt = 16 pi dh/dt
here dh/dt = 0.25 so dV/dt =?

Answer 3

the height isn't 11?

Answer 4

I thought the dh/dt is 11

Answer 5

and V is 0.25