Question

Please help me out. :)

Answer 1

It would help you to draw the diagram as a first step, interpreting values as you go.
Forces would be positive upwards, so forces A and D are negative.
Also, label forces so you can refer to them in your solution.
To find the resultant, as in your previous exercse, they would need to satisfy two conditions:
Let R = magnitude of resultant force (watch sign/direction)
Sum of forces =0: \(\Sigma F=0\),
\(\Sigma F = -50+40+R+20-60 N =0\)
Solve for F (watch sign, + up, -down)
Sum of moments = 0 : \(\Sigma F.d=0\)
You can take moments about any point, say A.
Give it a try and ask for help if you need any.