Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

.

OpenStudy (anonymous):

@ankit042

OpenStudy (anonymous):

The question asks for the confidence interval for the men not for the individual values, thus standard error of the mean = s.d./sqrt(n) is the correct measure of variability and we assume means are distributed normally..

OpenStudy (anonymous):

thankssss :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!