Given the functions j(x) = x2 - 9 and k(x) = -x + 7, which operation results in a 3rd degree polynomial?

Addition

Subtraction

Multiplication

No operations

Question

Given the functions j(x) = x2 - 9 and k(x) = -x + 7, which operation results in a 3rd degree polynomial?

 Addition

 Subtraction

 Multiplication

 No operations

anonymous · Answer

MULTIPLY

anonymous · Answer

you can't add variables with unequal exponents with each other, you can't subtract them.

adding them would get you: x² - x -2 (2nd degree polynomial)
subtracting them would get you: x²+x-16 (2nd degree polynomial)
multiplying: (x² -9) (-x + 7)= -x³ + 7x² -9x - 63 (3rd degree polynomial)

anonymous · Answer

sorry should be -x³+7x²+9x-63