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cos(2x-(Pi/10))=0 all solutions in interval [0,2pi)
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cos(2x) = cos (pi/10)
Think of the unit circle, at what angles does the value of x =0?
Pi/2, 3pi/2
Pi/2 and 3pi/4 right? So how to we get the 2x-pi/10 to equal the two angles I have? What will x need to be?
pi/20
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3pi/2 right, sorry!!
So if x=pi/20, then is the expression equal to one of the two angles It needs to be?
G2g, cya!
i don't know i got up to pi/20 ok thanks for your help
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