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Mathematics 22 Online
OpenStudy (anonymous):

What is the vertex of the graph of y = −4(x + 2)^2 + 5?

OpenStudy (anonymous):

(2, 5) (−2, 5) (5, −2) (5, 2)

OpenStudy (anonymous):

(-2,5)

OpenStudy (anonymous):

How?

OpenStudy (anonymous):

its genreAL eq.. y=(x-a)^2+h here vertex=(a,h) so for thiis eq =(-2,5)

OpenStudy (anonymous):

\[-b/2a\]

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