Question

64^-1/3

Answer 1

\[\Huge a^{-\frac{1}{n}}=\frac{1}{a^n}\]

Answer 2

so, one over 64 to the 3rd?

Answer 3

\[\Large 64^{-\frac{1}{3}}=\frac{1}{64^{\frac{1}{3}}}=\frac{1}{\sqrt[3]{64}}\]

Answer 4

that's not right; see: \[\Huge a^{-\frac{1}{n}} = \dfrac{1}{a^{\frac{1}{n}}}\]

Answer 5

well, doulikepiecauseidont's second reply is correct