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\[\frac{ -x^2-3x+4 }{ x^2-x-2 }\]
Identify the points of discontinuity, holes, vertical asymptotes, x-intercept, horizontal asymptote, and domain of each. Then sketch the graph.
\[\frac{ -(x^2+3x-4) }{x^2-x-2 }=\\\frac{ -(x-1)(x+4)}{(x+1)(x-2) }\]
howd we go from logs to this??
points of discontinuity x=-1,2 vertical asymptotes x=-1,2 x-intercept when f(x)=0 so -(x-1)(x+4)=0 x=1,-4 horizontal asymptote lim f(x)=-1 so y=-1
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