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HELP PLEASE! T varies inversely with the cube of W When W is 3 T is 1/9 find the value of W when T is 1/243
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@LarsEighner @ikram002p
post the whol Qn plz :)
@ikram002p here you go
\(T \text{ }\alpha \text{ } \dfrac{1}{w}\) means \(T \text{ }= \text{ } \dfrac{k}{w}\) s.t k is constant \( \dfrac{1}{9} \text{ }= \text{ } \dfrac{k}{3}\) so \(k=\dfrac{1}{3}\) equation become \(T = \dfrac{1}{3w}\)
so \(T = \dfrac{1}{3w}\) \(\dfrac{1}{243} = \dfrac{1}{3w}\) solve for w
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