Question

Equation of tangent to a curve?

Answer 1

\(x=1+4t-t^2\),

\(y=2-t^3\)

with the given value of \(t=1\)

Answer 2

find dy/dt
then dx/dt

divide those and you get dy/dx

Answer 3

then you need a point
put t=1, find x and y
that will be your point

Answer 4

Would I need to simplify the derivative or could I just use it as it is?

Answer 5

to find the slope, right ?
no need to simplify, you will anyways plug the points in it!

Answer 6

Alright, thanks hartnn :)

Answer 7

welcome ^_^