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Mathematics 8 Online
OpenStudy (anonymous):

the zoo needed to raise $25,000. zoo officials decided to do dinner/dance event and charged $300 per couple. what is the fewest number of people that would need to attend in order for the goal to be meet?

OpenStudy (dangerousjesse):

Omg so many fake photos. Just solve for x and round down to the nearest whole number. \[25,000\div300=x\]

OpenStudy (anonymous):

0.012?

OpenStudy (anonymous):

.... 83.33......... and so on what i got

OpenStudy (kanwal32):

see if for one couple he is charging 300$ so for so to collect 25000$ he will need 25000/300 so 81 couples

OpenStudy (kanwal32):

so he cannot call 83.3333 couples so he needs to call 81 couples

OpenStudy (anonymous):

so how many people? do i divide by two cause it couples and it says how many people

OpenStudy (dangerousjesse):

No, he needs to call 84.

OpenStudy (kanwal32):

y

OpenStudy (dangerousjesse):

He's aiming for a minimum of 25000 dollars, so he needs to go over 83.3

OpenStudy (kanwal32):

oh sorry

OpenStudy (dangerousjesse):

The closest whole number to 83.3 is 84.

OpenStudy (anonymous):

wrong!

OpenStudy (kanwal32):

84 (silly mistakes)

OpenStudy (kanwal32):

lol

OpenStudy (dangerousjesse):

No, I'm not Sarah. The correct answer is 84.

OpenStudy (anonymous):

well A+pls said u wrong

OpenStudy (kanwal32):

i was thinking about something else

OpenStudy (dangerousjesse):

Whoever that is is wrong. \[25000\div300=83.333333333\] There's no such thing as .33333 people, so you'll round up to one whole person. 84.

OpenStudy (kanwal32):

i was saying the same thing but i wrote 81 by mistake

OpenStudy (dangerousjesse):

Mind giving me a medal for working this out for you?

OpenStudy (kanwal32):

yes

OpenStudy (kanwal32):

i've given it to @sarah_12

OpenStudy (dangerousjesse):

I meant @sarah_12

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