Question

H(x)=(x^2)+1 and K(x)=-(x^2)+4. If K(H)=0, what are the roots/solutions?
a. ±i√3
b. ±i
c. ±2
d. ±1
e. ±1, ±i√3

Answer 1

\(\bf H(x)=x^2+1\qquad K(x)=-x^2+4
\\ \quad \\
K(H)=-(x^2+1)^2+4\qquad thus \quad K(H)=0\to 0=-(x^2+1)^2+4\)

solve for "x"