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halp function problems are killing me
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so I think it'd be cubed root x+2 over cubed root x+3 but I have no idea how to do that
\(h(x) = f(~g(x)~) = \sqrt[3]{g(x) + 2}\) So what g have to be for f( g(x) ) to be \(\sqrt[3]{x+3}\)?
\(\large \begin{array}{llll} f(x)=\sqrt[3]{x+2}\qquad {\color{brown}{ g(x)}}\\ \hline\\ f(\quad {\color{brown}{ g(x)}}\quad )=\sqrt[3]{x+3}\qquad and \\ \quad \\ f(\quad {\color{brown}{ g(x)}}\quad )=\sqrt[3]{{\color{brown}{ g(x)}}+2} \end{array}\qquad thus \sqrt[3]{x+3} = \sqrt[3]{{\color{brown}{ g(x)}}+2}\) any ideas?
g(x)= x+1?
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yeap
thanks guys!
yw
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