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solve the equation in the real number system x^3-(3/4)x^2+(47/4)x+3=0
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http://www.wolframalpha.com/input/?i=x^3-%283%2F4%29x^2%2B%2847%2F4%29x%2B3%3D0
apparently it is \(-\frac{1}{4}\) not sure how you would have found it
maybe start with \[4x^3-3x^2+47x+12=0\] but still not sure how you are going to get the answer
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