help with indefinite integral

Question

anonymous · Answer

anonymous · Answer

338/9+(26 t)/3+t^2-320/9 log(13+3 t)

anonymous · Answer

the answer above isn't correct even though i worked it out in the previous thread

luigi0210 · Answer

Use long division to simplify it.

anonymous · Answer

the program calls for an absolute value

anonymous · Answer

but im not quite sure what you mean by long division here

anonymous · Answer

here's the question lol

anonymous · Answer

let u = 3t+13  and t =(u-13)/3
dt =(1/3 )du
and so on..

anonymous · Answer

Have you tried integration by parts ?

anonymous · Answer

anonymous · Answer

here u may not need integration by parts but it is simple substituition problems..

anonymous · Answer

ok can someone work through it while i take notes. im confused at this point

anonymous · Answer

id really appreciate it

nincompoop · Answer

where is your attempt at solving this problem?

anonymous · Answer

nincompoop · Answer

yeah I saw that... that was a lot of help given to you to a point it was spoon-feeding you the answer 

where is your attempt

anonymous · Answer

well that answer wasn't correct in the end.

nincompoop · Answer

so where is your attempt?

anonymous · Answer

idk what exactly you're getting at but here's my answer t^2+(26t/3)-(320/9)ln(3t+13)+(338/9)

nincompoop · Answer

so you have an answer... why are you still looking for help? 
do you want us to validate your answer before you submit it and get perfect scores?

anonymous · Answer

no because its wrong. already had the program validate it

nincompoop · Answer

okay
6 integral (t/3+160/(9 (3 t-13))+13/9) dt

anonymous · Answer

doesn't work :/

anonymous · Answer

1/9 (9 t^2+78 t+320 logabs((3 t-13))-507) ?

anonymous · Answer

@nincompoop that doesn't work..