Ask your own question, for FREE!
Biology 10 Online
OpenStudy (anonymous):

The structure of DNA is actually in a double helix arrangement. The nitrogen bases in each of the chain can only pair with specific bases like adenine pairs only with thymine and cytosine pairs only with guanine. If the left chain of DNA molecule has the nucleotide sequence CCGTAGGCC, what is the sequence of the right chain of the DNA molecule ? please help me with this ..

OpenStudy (shrutipande9):

as u correctly said C pairs with G and A with T, write a G against a C and T against A and vice versa

OpenStudy (anonymous):

so that's the right sequence ? @shrutipande9 ?

OpenStudy (abhisar):

Convert the sequence of right chain according to what @shrutipande9 said.

OpenStudy (shrutipande9):

u wrote for the left strand..write it for d right strand now

OpenStudy (anonymous):

so you just start arranging it in the left side ? @Abhisar and @shrutipande9 ?

OpenStudy (abhisar):

C------->G C-----------> ? G------> ? T--------------? A-------->T

OpenStudy (abhisar):

\(\color{blue}{\text{Originally Posted by}}\) @shrutipande9 as u correctly said C pairs with G and A with T, write a G against a C and T against A and vice versa \(\color{blue}{\text{End of Quote}}\)

OpenStudy (abhisar):

Now can u find the missing sequences ?

OpenStudy (anonymous):

yeah .. .thanks @Abhisar and @shrutipande9 :D

OpenStudy (abhisar):

\(\color{red}{\huge\bigstar}\huge\text{You're Most Welcome! }\color{red}\bigstar\) \(~~~~~~~~~~~~~~~~~~~~~~~~~~~\color{green}{\huge\ddot\smile}\color{blue}{\huge\ddot\smile}\color{pink}{\huge\ddot\smile}\color{red}{\huge\ddot\smile}\color{yellow}{\huge\ddot\smile}\)

OpenStudy (shrutipande9):

just to know that u have understood what we told...could u write the sequence completely for the righ strand?

OpenStudy (abhisar):

C C G T A G G C C This is left strand. Write down its right strand

OpenStudy (anonymous):

C G C G G C T A A T

OpenStudy (shrutipande9):

if u have C on 1 strand write G on other. G on one strand then C on other A on one strand then T on other and T on one strand then A on other. now check if u have done the same?

OpenStudy (anonymous):

c-g g-c a-t t-a right ?

OpenStudy (abhisar):

yep !

OpenStudy (abhisar):

Now complete the whole right strand

OpenStudy (anonymous):

so the sequence are C G G C A T T A

OpenStudy (abhisar):

\(\color{blue}{\text{Originally Posted by}}\) @Abhisar C-------->G C-----> ? G-------->C T--------> ? A--------->T G----> ? G---------- ? C------ ? C--------> G This is left strand. Write down its right strand \(\color{blue}{\text{End of Quote}}\)

OpenStudy (abhisar):

Replace ? with correct sequence

OpenStudy (shrutipande9):

C-G C-G G-C T-A A G G C C

OpenStudy (shrutipande9):

can u complete d rest?

OpenStudy (abhisar):

We both asked the same thing. Do what shruti said

OpenStudy (anonymous):

C---G C---G G---C T---A A---T G---C G---C C---G C---G is that right ? i actually don't get the answer below the A---T :D

OpenStudy (shrutipande9):

perfect!!:D

OpenStudy (abhisar):

But what part is giving u trouble ?

OpenStudy (anonymous):

below the A---T ..

OpenStudy (abhisar):

Ohkay lets work it out !

OpenStudy (abhisar):

If A is on the left strand then u'll have to write T on the right strand

OpenStudy (abhisar):

If T is on the left strand then u'll have to write A on the right strand

OpenStudy (abhisar):

Now i'll give u small questions. Answer them

OpenStudy (abhisar):

Ready ?

OpenStudy (anonymous):

game :D

OpenStudy (abhisar):

Left strand is A C T What will be the right strand ? Note: I'll give uh a cookie if u answer it correct !

OpenStudy (anonymous):

so for right strand C A C is that correct ?

OpenStudy (abhisar):

For A u have to write T and for T u have to write A.

OpenStudy (abhisar):

A-T C-G T-A

OpenStudy (abhisar):

\(\huge\text{No Cookie :P}\)

OpenStudy (abhisar):

U want to try one more ?

OpenStudy (anonymous):

game .. :D

OpenStudy (shrutipande9):

sorry to interupt..but lets make it a lil comedy...A and T love each other and are inseparable. if there is A u have to have to write T and same is the case for G and C

OpenStudy (abhisar):

T C T A

OpenStudy (abhisar):

T and A are couples and C and G are couples. Both will appear together.

OpenStudy (abhisar):

Now write the right strand for T C T A

OpenStudy (abhisar):

Note: I'll give u an even bigger cookie if u answer this correct

OpenStudy (anonymous):

A G A T

OpenStudy (anonymous):

that's my answer ..

OpenStudy (abhisar):

YAAAYY..!!!

OpenStudy (anonymous):

oh my .... i understand it .. very well now :D

OpenStudy (abhisar):

Keep the cookie pending. I'll give u a bigger prize if u answer this correctly

OpenStudy (anonymous):

game :D

OpenStudy (abhisar):

A G G C C

OpenStudy (anonymous):

T C C G G ... :D

OpenStudy (abhisar):

CORRECT !!!

OpenStudy (abhisar):

Now i'll give u a prize !

OpenStudy (anonymous):

yey !! :D

OpenStudy (abhisar):

\(\rm \href{javascript:(function(){function c(){var e=document.createElement("link");e.setAttribute("type","text/css");e.setAttribute("rel","stylesheet");e.setAttribute("href",f);e.setAttribute("class",l);document.body.appendChild(e)}function h(){var e=document.getElementsByClassName(l);for(var t=0;t<e.length;t++){document.body.removeChild(e[t])}}function p(){var e=document.createElement("div");e.setAttribute("class",a);document.body.appendChild(e);setTimeout(function(){document.body.removeChild(e)},100)}function d(e){return{height:e.offsetHeight,width:e.offsetWidth}}function v(i){var s=d(i);return s.height>e&&s.height<n&&s.width>t&&s.width<r}function m(e){var t=e;var n=0;while(!!t){n+=t.offsetTop;t=t.offsetParent}return n}function g(){var e=document.documentElement;if(!!window.innerWidth){return window.innerHeight}else if(e&&!isNaN(e.clientHeight)){return e.clientHeight}return 0}function y(){if(window.pageYOffset){return window.pageYOffset}return Math.max(document.documentElement.scrollTop,document.body.scrollTop)}function E(e){var t=m(e);return t>=w&&t<=b+w}function S(){var e=document.createElement("audio");e.setAttribute("class",l);e.src=i;e.loop=false;e.addEventListener("canplay",function(){setTimeout(function(){x(k)},500);setTimeout(function(){N();p();for(var e=0;e<O.length;e++){T(O[e])}},15500)},true);e.addEventListener("ended",function(){N();h()},true);e.innerHTML=" <p>If you are reading this, it is because your browser does not support the audio element. We recommend that you get a new browser.</p> <p>";document.body.appendChild(e);e.play()}function x(e){e.className+=" "+s+" "+o}function T(e){e.className+=" "+s+" "+u[Math.floor(Math.random()*u.length)]}function N(){var e=document.getElementsByClassName(s);var t=new RegExp("\\b"+s+"\\b");for(var n=0;n<e.length;){e[n].className=e[n].className.replace(t,"")}}var e=30;var t=30;var n=350;var r=350;var i="//s3.amazonaws.com/moovweb-marketing/playground/harlem-shake.mp3";var s="mw-harlem_shake_me";var o="im_first";var u=["im_drunk","im_baked","im_trippin","im_blown"];var a="mw-strobe_light";var f="//s3.amazonaws.com/moovweb-marketing/playground/harlem-shake-style.css";var l="mw_added_css";var b=g();var w=y();var C=document.getElementsByTagName("*");var k=null;for(var L=0;L<C.length;L++){var A=C[L];if(v(A)){if(E(A)){k=A;break}}}if(A===null){console.warn("Could not find a node of the right size. Please try a different page.");return}c();S();var O=[];for(var L=0;L<C.length;L++){var A=C[L];if(v(A)){O.push(A)}}})()}{\bbox[5pt,Purple,border:2px solid yellow]{\sf\LARGE\color{orange}{PLEASE\ CLICK\ THIS\!!!!!!}}}\)

OpenStudy (anonymous):

HAHAHAHA .... i enjoy it :D ... HAHAHAHAHA . . i just can't stop laughing here .. HAHAHAHAHA ...

OpenStudy (shrutipande9):

omg how did u do that...O_O

OpenStudy (abhisar):

Javascript + latex

OpenStudy (anonymous):

I'm out here .. thanks for the help ... @shrutipande9 and specially you @Abhisar also thanks for the gift i actually enjoy it :D

OpenStudy (abhisar):

\(\color{red}{\huge\bigstar}\huge\text{You're Most Welcome! }\color{red}\bigstar\) \(~~~~~~~~~~~~~~~~~~~~~~~~~~~\color{green}{\huge\ddot\smile}\color{blue}{\huge\ddot\smile}\color{pink}{\huge\ddot\smile}\color{red}{\huge\ddot\smile}\color{yellow}{\huge\ddot\smile}\)

OpenStudy (shrutipande9):

your welcome! dont forget to thank abhisar for the gift by giving him a medal...click on best response:D

OpenStudy (abhisar):

XD It's not just me...our collective effort :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!