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Trigonometry
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can anyone simplifiy this (csc(θ) (1-cos(θ)^2 ))/cos(θ)
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\(1 - \cos^2\theta) = \sin^2 \theta \)
\(\csc\theta = {1 \over {\sin\theta}}\)
so the numerator is \( {1\over{\sin\theta}}(\sin^2\theta) = \sin\theta\)
\( {{\sin\theta} \over {\cos\theta}} = \tan\theta \)
thanks for that, I am a bit older than the average student and appreciate your reply
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