Question

(8x-8)(8x+8)

Answer 1

\(64x^2 - 64 \)

Answer 2

remember this formula
\(\Huge \color{pink}{(a+b)(a-b)=a^2-b^2}\)
but if u wanna to find zero of
\(\Huge \color{pink}{(y+b)(y-b)=0}\)
then
\(\Huge \color{pink}{ y=-b , y=b} \)

Answer 3

There are a few ways to proceed. Here's one that has not yet been suggested.

(8x+8)(8x-8) = 8(x+1)8(x-1) = 8*8*(x+1)*(x-1) = 64(x^2 - 1)

Answer 4

@LarsEighner is correct

Answer 5

:)

Answer 6

@cmckie Actually, ikram002p and tkhunny are more correct, since their responses were not in direct violation of he Code of Conduct.