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Tangent line problem
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key states it is C
what is slope? aka \(f'(3)\)?
2
I wrote down 0, I was looking at the graph of f(x) but now I see my graph is f ' (x) ok thanks....
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It is C
funny, C is not right, unless im missing sometihng...
@ganeshie8 any idea?
@TuringTest @texaschic101 @Compassionate
The graph given is f ' (x)
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ohh, right... so you can see that f(3) = 2
damn f'(3) = 2**
I always have to remind myself that I am looking at f ' (x) and not f(x)
Use this formula: \[y-y_1 = m(x-x_1)\] we got slope, now what's left is point. do you know how to find it?
yes, I know how to sub into the formula, thanks
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welcome :)
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