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Write in standard form an equation of the line passing through the given point with the given slope. Slope= 1/6; (-1,5) a. x + 6y = 31 b. -x + 6y = -31 c. -x - 6y = 31 d. x - 6y = -31
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\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ -1}}\quad ,&{\color{blue}{ 5}})\quad \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{1}{6} \\ \quad \\ y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and move everything to the left}\\ \qquad \uparrow\\ \textit{point-slope form}\)
Thank you :D
yw
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