How many 3 digit numbers are divisible by both 3 and 5 but not by 7?
if you know set theory and probablity, no of digit divisible by 3 and 5 but not 7 = no of digits divisible by 3+ no of digits divisible by 5 - no of digits divisible by both 3 and 5+ no. of digits divisible by 105 (i got this as the lcm of 3,5 n 7) hope this helps. dont forget to mark this as the best response (y)
no of digit divisible by 3 and 5 but not 7 = no of digits divisible by 3+ no of digits divisible by 5 - no of digits divisible by both 3 and 5 \(\color{red}{-}\) no. of digits divisible by 105
333+199-66-95=371
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