Find the approximate length of the leg of a right triangle with one leg length 8 and hypotenuse length 19.
Ok so we got two parts here
okie.
My bad sorry for the confusion lol i havent had coffee .
Its all good haha
Hypotenuse = c a2+b2=c282+92=c2=145c=145and then that equals????
.... whut...
First, write down the pythagorean theorem (very famous) \[ a^2 + b^2 = c^2 \] a and b are the "legs" c is the hypotenuse. replace the letter a with the length of the leg replace the letter c with the len of the hypotenuse can you do that ?
Okay I got it.
Like this basically a^2+b^2=c^2 8^2+9^2=c^2=145 c=√145=__.__
I dont know who I should give the medal to . You both did very well.
Well i gave phi a medal so win/win but the medal doesn't really matter
*** Okay I got it.*** what did you get. Can you write it down ? replace the letter a with the length of the leg replace the letter c with the len of the hypotenuse
Its about who will help you get the answer correct and get it done as a team
I got it too
I know how to do it now. Thanks guys!
What did you get tho?
trust me, you should work through this problem step by step.
20.61
Ur wrong
How?
its 12.04
Thats even a choice for the multiple choice.
1) write down the equation a^2 + b^2 = c^2 a and b are the legs, c is the hypotenuse 2) replace a with 8 and c with 19
Ik what i did wrong i did it for a 9 not 19 im ashamed listen to phi he/she knows what to do
Its 17.2
correct?
to "replace" a with 8 means erase the a and put in 8 replace c with 19 8^2 + b^2 = 19^2
now simplify 8^2 = 8*8 simplify 19^2 = 19*19 what do you get ?
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