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In the figure below, ∠DEC ≅ DCE, ∠B ≅ ∠F, and segment DF is congruent to segment DB. Point C is the point of intersection between segment AG and segment BD, while point E is the point of intersection between segment AG and segment DF.
SSS, SAS, ASA or AAS?
i do not get this part
Since DF=DE+EF, DB=DC+CB, DF=DB, DE+EF=DC+CB, then CB=EF angle DCE=angle ACB ( vertical angles) angle DEC=angle GEF (vertical angles) but angle DCE= angle DEC ( given) then angle ACB=angle GEF angle B=angle F ( given) CB=EF (proved) angle ACB= angle GEF ( proved ) then Triangles ABC and GFE are congruent
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