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Find the area of a regular octagon with apothem K and side of 10.
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\[A=\frac{ap}{2}\] where \(a\) is the length of the apothem and \(p\) is the perimeter.
For a regular octagon the area is given by 8×Apothem2×tan(π/8) Again, Side=2× Apothem ×tan(π/8) So use the second one to find the value of tan(π/8) and then substitute the value in the first which will give 40k as answer.
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