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Solve the system: y = 2x^2 + 2x - 1 y = -x^2 -x +5
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This is what I have so far: -x^2 - x + 5 = 2x^2 + 2x -1 0 = x^2 + x - 5 + 2x^2 + 2x- 1 0 = 3x^2+ 3x - 6
do i just do the quadratic formula?
Factor the 3 out first.
3x^2+ 3x - 6 = 0 3(x^2 + x - 2) = 0 x^2 + x - 2 = 0 x^2 + 2x - x - 2 = 0 x(x + 2) - 1(x + 2) = 0 (x+2)(x-1) = 0 x = -2 or 1.
wait where did the 2x come from?
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It is a way to factor a quadratic equation. The middle term x can be written as 2x - x
ah thank you so much! :)
You are welcome.
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