Question

Write log3 6 as a logarithm of base 2.

log base 2 of 3 over log base 2 of 6

log base 2 of 6 over log base 2 of 3

log base 3 of 2 over log base 6 of 2

log base 6 of 2 over log base 3 of 2

Answer 1

@campbell_st

Answer 2

the change of base formula is

\[\log_{a}(b) = \frac{\log_{c}(b)}{\log_{c}(a)}\]

so in your question a = 3, b = 6 and c = 2

just substitute for the answer

Answer 3

is the answer 3

Answer 4

or 8

Answer 5

there isn't a number answer its simply

\[\log_{3}(6) = \frac{\log_{2}(6)}{\log_{2}(3)}\]