Question

There are 13 animals in the bar. Some are chickens and some are pigs. There are 40 legs in all. How many of each animal are there?

Answer 1

they really stretch for these word problems, don't they?
try
\[x+y=13\\
2x+4y=40\]

Answer 2

You can make 2 equations based off this equation.
A chicken has two legs and a pig has four.
x+y=13
2x+4y=40

Solve these two systems of equations
x=13-y
2(13-y)+4y=40
26-2y+4y=40
2y+26+40
Subtract 26 on both sides
2y=14
Divide by 2 on both sides
y=7
x+7=13
x=6
So there are 6 chickens and 7 pigs.

Answer 3

thanks