Question

the perimeter of a rectangle is 52. the length is 6 greater than the width . find the length and the width of this rectangle.

Answer 1

First, write an equation. Let x= width and x+6= length (the length is 6 greater than the width). Hint- Perimeter=2L+2W

Answer 2

ok

Answer 3

im not sure

Answer 4

ok so, if the width is x, the length is x+6, and the perimeter is 52, do 2(x)+2(x+16)=52 since 2L+2W=52. Now, just solve for x. that is your width. to find your length, plug in x+6 with the number that you got for the width. that is your length

Answer 5

x=5

Answer 6

how did you get x=5?

Answer 7

i solved the equation

Answer 8

is the width 5

Answer 9

and the length 30

Answer 10

well if you solved the equation, you had to distribute. 2(x)+2(x+6) to get 2x+2x+12=52. Then, this becomes 4x+12=52

Answer 11

solve 4x+12=52 to find x. It is not 5.

Answer 12

your first reply said 16

Answer 13

?

Answer 14

the reply under "im not sure"

Answer 15

oh mb, typo -.- sorry. anyways
4x+12=52
4x=40
x=10.
x+6= 16
Width= 10
Length= 16
---------------
Check
2(10)+2(16)=52
20+32=52
52=52

Answer 16

Therefore, the width is 10 and the length is 16.

Answer 17

i reworked it and got those answers

Answer 18

:) sorry about the typo

Answer 19

no problem